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- 奇怪丶L 2021-01-25 10:55关注
select time,sum(num_log),sum(num_dev),sum(num_user)
(
select date(time) as time,sum(1) as num_log,0 as num_dev,0 as num_user from user_log group by date(time)
union all
select date(time) as time,0 as num_log,sum(1) as num_dev,0 as num_user from user_dev group by date(time)
union all
select date(time) as time,0 as num_log,sum(1) as num_dev,0 as num_user from user_user where status='1' group by date(time)
) group by time
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