帮】帮【忙大【佬 们，小 弟在此跪 谢了

Question

#include<stdio.h>
#include<stdlib.h>
int Not_Repeat(int* br, int n)
{
    int tmp = 0,i = 0;
    for (int i = 0; i <= n; i++)
    {
        int tmp = rand() % 100 + 1;
        if (tmp == br[i])
        {
            br[i] = tmp;
        }
        else
        {
            continue;
        }
    }
    br[n] = tmp;
    for (int i = 0; i < n; i++)
    {
        printf("%5d", br[i]);
    }
    if ((i + 1) % 5 == 0)
    {
        printf("\n");
    }
    return br[n];
}
void Init_Ar(int* br, int n)
{
    for (int i = 0; i < n; i++)
    {
        br[i] = rand() % 100 + 1;
    }
}



void Print_Ar(int* br,int n)
{
    for (int i = 0; i < n; i++)
    {
        printf("%4d", br[i]);
        if (int(i + 1) % 10 == 0)
        {
            printf("\n");
        }
    }
    printf("\n");

}

void BubbleSort(int* br, int n)
{
    int tmp;
    for (int j = 1; j < n; j++)  //比较的趟数
    {
        for (int i = 0; i < 99 - j; i++) //从下表i=0开始比较
        {
            if (br[i] > br[i + 1])
            {
                tmp = br[i];
                br[i] = br[i + 1];
                br[i + 1] = tmp;
            }
        }
    }
}

int main()
{
    const int n = 100;
    int ar[n] = {};
    sizeof(ar);
    Init_Ar(ar, n);
    Print_Ar(ar,n);
    Not_Repeat(ar, n);
    BubbleSort((int*)Not_Repeat(ar,n), n);
    Print_Ar(ar, n);
    
    return 0;

}

Answer 1

if ((i + 1) % 5 == 0)

这句话的i可能不是你想的那个i。这里的i是第一行定义的i，值一直是0.因为中间几个循环你又重新定义了i

BubbleSort((int*)Not_Repeat(ar,n), n);

这也很奇怪，Not_Repeat返回一个整型值，你强制转换成int*，想干啥呢？

把一个整型值当成地址，结果自然是崩溃了