python如何实现三个列表合并成为一个字典

Question

list1 = [['A'], ['A'], ['A'], ['A'], ['A'], ['B'], ['B'], ['B'], ['B'], ['B'], ['C'], ['C'], ['C'], ['C'], ['C'], ['D'],
         ['D'], ['D'], ['D'], ['D']]
list2 = [['a'], ['b'], ['c'], ['d'], ['e'], ['a'], ['b'], ['c'], ['d'], ['e'], ['a'], ['b'], ['c'], ['d'], ['e'], ['a'],
         ['b'], ['c'], ['d'], ['e']]
list3 = [[3.0], [4.0], [0.0], [3.5], [0.0], [4.0], [0.0], [4.5], [0.0], [3.5], [0.0], [3.5], [0.0], [0.0], [3.0], [0.0],
         [4.0], [0.0], [3.5], [3.0]]

最后输出为

dict = {
            "A": {"a": 3.0, "b": 4.0, "c": 0.0, "d": 3.5, "e": 0.0},
            "B": {"a": 4.0, "b": 0.0, "c": 4.5, "d": 0.0, "e": 3.5},
            "C": {"a": 0.0, "b": 3.5, "c": 0.0, "d": 0.0, "e": 3.0},
            "D": {"a": 0.0, "b": 4.0, "c": 0.0, "d": 3.5, "e": 3.0},
}

Answer 1

本来想用字典解析试试能不能一行写出来，后来发现还是写for循环思路清晰
直接用一个下标同时遍历三个列表，设计一个储存外层字典key（即遍历的上一个list1的元素值）的变量，当key发生改变说明需要在dict插入新的key，反之说明key已经存在，可以直接访问并修改已存在的内部字典

dict= {}
key = ''
inner_dict={}
for i in range(len(list1)):
    currrent_key = list1[i][0]
    inner_key = list2[i][0]
    inner_value = list3[i][0]
    if currrent_key != key :
        inner_dict = {inner_key:inner_value}
        dict[currrent_key] = inner_dict
    else:
        dict[currrent_key][inner_key] = inner_value
    key = currrent_key