C语言问题 使用位运算将浮点数乘以 2048

Question

请问这个要怎么解决？在“PUT YOUR CODE HERE”写内容，前面内容不要改动，按照要求来写，da佬编写1下，蟹蟹大lao，可以用下面的例子来测试是否正确。

// Multiply a float by 2048 using bit operations only

#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <assert.h>

#include "floats.h"

// float_2048 is given the bits of a float f as a uint32_t
// it uses bit operations and + to calculate f * 2048
// and returns the bits of this value as a uint32_t
//
// if the result is too large to be represented as a float +inf or -inf is returned
//
// if f is +0, -0, +inf or -inf, or Nan it is returned unchanged
//
// float_2048 assumes f is not a denormal number
//
uint32_t float_2048(uint32_t f) {
    // PUT YOUR CODE HERE

    return 42;
}

Answer 1

1024=2的10次方，2048=2的11次方，左移1位相当于乘以2，所以左移11位就相当于乘以2048
float a;
a << 11;