matlab程序解释一下每段是什么意思有什么作用

Question

t=-400:0.01:4; .

a = cos(t);

b = cos(4*t);

x = sin(t).(exp(a)-b2-

(sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12));

y = cos(t).(exp(a)-b2-

(sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12));

t1 =linspace(0,pi/3,40401);

x1=5*cos(t1)-5;

x2=-x1;

y1=5*sin(t1)+2.5;

y2=y1;

plot(x,y,m',x1,y1,m',x2,y2,'m')

axis off
帮忙解释一下每一段程序的意思

Answer 1

你好！解释如下

t=-400:0.01:4; .%t从-400到4取值，每间隔0.01
a = cos(t);%a取cos(t)
b = cos(4*t);%b取cos(4t)
x = sin(t).(exp(a)-b2-(sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12));%x对t求得函数值
y = cos(t).(exp(a)-b2-(sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12).*sin(t/12));%y对t求得函数值
t1 =linspace(0,pi/3,40401);%t1从0到pi/3取值，总共均匀取40401个点
x1=5*cos(t1)-5;%x1对t1的函数值求出来
x2=-x1;%x2是x1的相反数
y1=5*sin(t1)+2.5;%y1对t1的函数值
y2=y1;%y2等于y1
plot(x,y,m',x1,y1,m',x2,y2,'m')%画x-y函数图像，画x1-y1函数图像，同时画x2-y2函数图像
axis off%去掉坐标轴

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