#include <stdio.h>
#include <math.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>
#include<conio.h>
char CSV5();
int main(){
char p[100], PASSWORD[]=CSV5();
int i=0;
while(p[i]=getch())
{
if(p[i]==13){
break;
}
if(p[i]!='\b'){
printf("*");
i++;
}
else{
printf("\b \b");
i--;
}
}
p[i]='\0';
printf("\n");
if(strcmp(p,PASSWORD)==0)
{
printf("Yes\n");
}
else
{
printf("No\n");
}
return 0;
}
char CSV5(){
FILE *fp = NULL;
char *line,*record;
char buffer[1024];
if((fp = fopen("transaction.csv", "r")) != NULL)
{
fseek(fp, 0L, SEEK_SET);
char delims[] = ",";
char *result = NULL;
int j = 0;
while ((line = fgets(buffer, sizeof(buffer), fp))!=NULL)
{
record = strtok(buffer, ",");
while (record != NULL)
{
if (strcmp(record, "Ps") == 0)
return *record;
if (j == 9)
break;
record = strtok(NULL, ",");
j++;
}
j = 0;
}
fclose(fp);
fp = NULL;
}
}
C语言 想读取CSV文件里面的数字作为password 但是不知道怎么把里面的东西表示出来并用一个变量表示
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1条回答 默认 最新
- 书山客 2021-12-16 19:47关注
#include <stdio.h> #include <math.h> #include <string.h> #include <ctype.h> #include <stdlib.h> #include<conio.h> char* CSV5(); int main() { char p[100], *PASSWORD; int i = 0; while (p[i] = getch()) { if (p[i] == 13) { break; } if (p[i] != '\b') { printf("*"); i++; } else { printf("\b \b"); i--; } } p[i] = '\0'; printf("\n"); PASSWORD = CSV5(); if (strcmp(p, PASSWORD) == 0) { printf("Yes\n"); } else { printf("No\n"); } return 0; } char* CSV5() { FILE* fp = NULL; char* line, * record; char buffer[1024]; if ((fp = fopen("transaction.csv", "r")) != NULL) { fseek(fp, 0L, SEEK_SET); char delims[] = ","; char* result = NULL; int j = 0; while ((line = fgets(buffer, sizeof(buffer), fp)) != NULL) { record = strtok(buffer, ","); while (record != NULL) { if (strcmp(record, "Ps") == 0) return record; if (j == 9) break; record = strtok(NULL, ","); j++; } j = 0; } fclose(fp); fp = NULL; } return 0; }
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