关于C++异常抛出常量字符串无法被char*捕获

Question

关于C++异常抛出问题

用throw抛出一个常量字符串,我验证过后发现这个常量字符串无法抛出,且一直报错,希望大神解答

#include <iostream>
using namespace std;


void My_Strcpy(char* des, char* src) {
    if (des == NULL) {
        throw "拷贝目的出错";
    }
    if (src == NULL) {
        throw "拷贝源出错";
    }
/*
    实验失败,用throw抛出的常量字符串根本无法抛出
    失败原因未知
*/
    if (*src == 'a') {
        throw "拷贝过程出错";
    }
    while (*src !='\0') {
        *des = *src;
        des++;
        src++;
    }
    *des = '\0';
}

int main() {

    char buf1[] = "anndwoa";
    char buf2[1024] = { 0 };
    try
    {
        My_Strcpy(buf2, buf1);
    }
    catch (int e)
    {
        cout << e << "int类型错误" << endl;
    }
    catch (char *e)
    {
        cout << e << "char*类型错误" << endl;
    }
    printf("%s \n", buf2);
    cout<<"hello....."<<endl;
    system("pause");
    return 0;
}

Answer 1

试试看const char*