c语言printf应用，求解难题

Question

输出样式
Rank Number Ratio

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Excellent 684 3.0%
Good 3290 14.6%
Medium 7512 33.4%
Pass 10958 48.7%
Fail 37 0.2%

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Total 22481 100.0%
我的代码
#include<stdio.h>
int main(void){ int Excellent,Good,Medium,Pass,
Fail;
scanf("%d%d%d%d%d",&Excellent,&Good,&Medium,&Pass,&Fail);
float a,b,c,d,e,h;
printf("Rank Number Ratio\n"); printf("-----------------------\n"); printf("Excellent%7d %.1f%%\n",Excellent,a=(float) Excellent/(Excellent+Good+Medium+Pass+Fail)*100); printf("Good%12d %.1f%%\n",Good,b=(float) Good/(Excellent+Good+Medium+Pass+Fail)*100); printf("Medium%10d %.1f%%\n",Medium,c=(float) Medium/(Excellent+Good+Medium+Pass+Fail)*100); printf("Pass%12d %.1f%%\n",Pass,d=(float) Pass/(Excellent+Good+Medium+Pass+Fail)*100); printf("Fail%12d %.1f%%\n",Fail,e=(float) Fail/(Excellent+Good+Medium+Pass+Fail)*100); printf("-----------------------\n"); printf("Total%11d %.1f%%\n",Excellent+Good+Medium+Pass+Fail,h=(float)(a+b+c+d+e)); return 0;}
结果报错：运行一样，格式错误，求解

Answer 1

说清楚题目要求

#include <stdio.h>
int main(void)
{
    int Excellent, Good, Medium, Pass,
        Fail;
    scanf("%d%d%d%d%d", &Excellent, &Good, &Medium, &Pass, &Fail);
    float a, b, c, d, e, h;
    // printf("Rank Number Ratio\n");
    printf("-----------------------\n");
    printf("Excellent %d %.1f%%\n", Excellent, a = (float)Excellent / (Excellent + Good + Medium + Pass + Fail) * 100);
    printf("Good %d %.1f%%\n", Good, b = (float)Good / (Excellent + Good + Medium + Pass + Fail) * 100);
    printf("Medium %d %.1f%%\n", Medium, c = (float)Medium / (Excellent + Good + Medium + Pass + Fail) * 100);
    printf("Pass %d %.1f%%\n", Pass, d = (float)Pass / (Excellent + Good + Medium + Pass + Fail) * 100);
    printf("Fail %d %.1f%%\n", Fail, e = (float)Fail / (Excellent + Good + Medium + Pass + Fail) * 100);
    printf("-----------------------\n");
    printf("Total %d %.1f%%\n", Excellent + Good + Medium + Pass + Fail, h = (float)(a + b + c + d + e));
    return 0;
}