为什么输入后没有输出

Question

#include<stdio.h>
int main()
{
    int i=1,n;
    printf("[1] crisps\n");
    printf("[2] popcorn\n");
    printf("[3] chocolate\n");
    printf("[4] cola\n");
    printf("[0] exit\n");
    for(i=1;i<=5;i++)
    {
        scanf("%d",&n);
        if(n==0)
        printf("Thanks\n");
        break;
        switch(n)
        {
            case 1:
                printf("price = 3.0");
                break;
            case 2:
                printf("price = 2.5");
                break;
            case 3:
                printf("price = 4.0");
                break;
            case 4:
                printf("price = 3.5");
                break;
            default:
                printf("price = 0");
                break;
        }
        printf("Thanks");
    }
    return 0;
}

Answer 1

 if(n==0)
        printf("Thanks\n");
        break;

if后要执行的语句用括号括起来

if(n==0)
   {
        printf("Thanks\n");
        break;
   }