php处理数组重复值问题

Question

        $arr = array(
            1,1,2,2,2,2,3,3,3,4,4,4,4,4,5,5,5,5
        );

这样一个数组,我想要给重复的值进行重新编号,组成如下数组的样子,求解

            $arr2 = array(
                    0=>['value'=>1,'num'=>1],
                    1=>['value'=>1,'num'=>1],
                    2=>['value'=>2,'num'=>2],
                    3=>['value'=>2,'num'=>2],
                    4=>['value'=>2,'num'=>2],
                    5=>['value'=>2,'num'=>2],
                    6=>['value'=>3,'num'=>1],
                    7=>['value'=>3,'num'=>1],
                    8=>['value'=>3,'num'=>1],
                    9=>['value'=>4,'num'=>2],
                    10=>['value'=>4,'num'=>2],
                    11=>['value'=>4,'num'=>2],
                    12=>['value'=>4,'num'=>2]
            );

想到办法了,不过我觉得我这样写好像有点儿繁琐,比较笨,下面是实现代码,欢迎大家提供更多思路

$arr = array(
            1,1,2,2,2,2,3,3,3,4,4,4,4,4,5,5,5,5
        );
        $newArray = [];//最后成型的新数组
        $arrCount = array_count_values($arr);//获取重复的元素每个的数量
        $newarrCount = array_values($arrCount);//重置重复元素数组的key
        $arrCountKey = array_keys($arrCount);//获取重复元素
        foreach($newarrCount as $k=>$v)//循环这个数组,根据奇偶数替换成1和2
        {
            if($k%2 == 0)
            {
                $newarrCount[$k] = 1;
            }else{
                $newarrCount[$k] = 2;
            }
        }
        $finArray = [];//中间最终数组
        foreach($newarrCount as $k=>$v)
        {
            $finArray[$arrCountKey[$k]] = $v;
        }

        foreach($arr as $k=>$v)
        {
            $newArray[$k]['value'] = $v;
            $newArray[$k]['num'] = $finArray[$v];
        }
        var_dump($newArray);

Answer 1

直接上代码

<?php
$arr = [1,1,2,2,2,2,3,3,3,4,4,4,4,4,5,5,5,5];
sort($arr);
$arr2 = [];
$num = 0;
$befor = $arr[0];
foreach($arr as $value){
    if($value != $befor){
        ++$num;
        $befor = $value;
    }
    $arr2[] = [
        'value' => $value,
        'num' => $num % 2 + 1
    ];
}

var_dump($arr2);