编程介的小学生 2019-06-19 19:23 采纳率: 20.5%
浏览 127

计算最省钱的挖水井的方法,怎么用C语言的程序设计的编写的过程来实现这个的计算

Problem Description
You may all know the famous story “Three monks”. Recently they find some places around their temples can been used to dig some wells. It will help them save a lot of time. But to dig the well or build the road to transport the water will cost money. They do not want to cost too much money. Now they want you to find a cheapest plan.

Input
There are several test cases.
Each test case will starts with three numbers n , m, and p in one line, n stands for the number of monks and m stands for the number of places that can been used, p stands for the number of roads between these places. The places the monks stay is signed from 1 to n then the other m places are signed as n + 1 to n + m. (1 <= n <= 5, 0 <= m <= 1000, 0 <=p <= 5000)
Then n + m numbers followed which stands for the value of digging a well in the ith place.
Then p lines followed. Each line will contains three numbers a, b, and c. means build a road between a and b will cost c.

Output
For each case, output the minimum result you can get in one line.

Sample Input
3 1 3
1 2 3 4
1 4 2
2 4 2
3 4 4
4 1 4
5 5 5 5 1
1 5 1
2 5 1
3 5 1
4 5 1

Sample Output
6
5

  • 写回答

0条回答 默认 最新

    报告相同问题?

    悬赏问题

    • ¥15 Power query添加列问题
    • ¥50 Kubernetes&Fission&Eleasticsearch
    • ¥15 有没有帮写代码做实验仿真的
    • ¥15 報錯:Person is not mapped,如何解決?
    • ¥30 vmware exsi重置后登不上
    • ¥15 易盾点选的cb参数怎么解啊
    • ¥15 MATLAB运行显示错误,如何解决?
    • ¥15 c++头文件不能识别CDialog
    • ¥15 Excel发现不可读取的内容
    • ¥15 关于#stm32#的问题:CANOpen的PDO同步传输问题