C语言函数指针中一段代码格式请教

Question

kandryte k210的SDK中断处理程序

代码片段

#define IRQ_M_SOFT 3
#define IRQ_M_TIMER 7
#define IRQ_M_EXT 11

typedef unsigned long int    uintptr_t;

uintptr_t __attribute__((weak))
handle_irq(uintptr_t cause, uintptr_t epc, uintptr_t regs[32], uintptr_t fregs[32])
{
#if defined(__GNUC__)
#pragma GCC diagnostic ignored "-Woverride-init"
#endif
    /* clang-format off */
    static uintptr_t (* const irq_table[])(
        uintptr_t cause,
        uintptr_t epc,
        uintptr_t regs[32],
        uintptr_t fregs[32]) =
    {
        [0 ... 14]    = handle_irq_dummy,
        [IRQ_M_SOFT]  = handle_irq_m_soft,
        [IRQ_M_TIMER] = handle_irq_m_timer,
        [IRQ_M_EXT]   = handle_irq_m_ext,
    };
    /* clang-format on */
#if defined(__GNUC__)
#pragma GCC diagnostic warning "-Woverride-init"
#endif
    return irq_table[cause & CAUSE_MACHINE_IRQ_REASON_MASK](cause, epc, regs, fregs);
}

问题

=后面的是函数指针，这段代码那些方括号是啥意思，

{
        [0 ... 14]    = handle_irq_dummy,
        [IRQ_M_SOFT]  = handle_irq_m_soft,
        [IRQ_M_TIMER] = handle_irq_m_timer,
        [IRQ_M_EXT]   = handle_irq_m_ext,
    };

Answer 1

这是赋值语句，将函数指针赋值给函数指针数组，[0 ... 14] = handle_irq_dummy, [0 ... 14]标识第0位到第14位赋值为handle_irq_dummy，个人是这样理解的。后面三个同理