c++代码问题继承与派生

Question

#include<iostream>
using namespace std;
class Animal{
    protected:
        unsigned int Age;double Weight;string Name;
    public:
        Animal(unsigned int age,double weight,string name)
        {
            Age=age;
            Weight=weight; 
            Name=name;
        }
        virtual void Animal()
        {
            cout << "Animal Constructor" << endl;
        }
};
class Fish:virtual public Animal{
    protected:
        bool Fim;
    public:
        Fish(unsigned int age,double weight,string name,bool Fim):Animal(age,weight,name)
        {
            this->Fim=Fim;
        }
        virtual void Fish()
        {
           cout << "Fish Constructor" << endl;
        }
};
class TerrestrialAnimal:virtual public Animal{
    protected:
        unsigned int Legs;
    public:
        TerrestrialAnimal(unsigned int age,double weight,string name,unsigned Leg):Animal(age,weight,name)
        {
            Legs=Leg;
        }
        virtual void TerrestrialAnimal()
        {
            cout << "TerrestrialAnimal Constructor" << endl;
        }
};
class Reptile:public Fish,public TerrestrialAnimal{
    public:
        Reptile(unsigned int age,double weight,string name,unsigned int Leg,bool Fim):Animal(age,weight,name),Fish(age,weight,name,Fim),TerrestrialAnimal(age,weight,name,Leg)
        {}
    virtual void Reptile()
    {
        cout << "Reptile Constructor" << endl;
    }    
    void Reptile::Print()
    {
        cout << "Reptile Age:" << Age << endl;
    }
};
int main(){
    int age;
    int weight;
    string name;
    int fim_num;
    int leg_num;
    cin >> age >> weight >> name >> fim_num >> leg_num;
    Reptile r1(age, weight, name, fim_num, leg_num);
    r1.Print();
    return 0;
}
        

代码出错了，请问一下怎么改
原本的代码要求如下
定义一个动物 (Animal) 基类，具有 Age、Weight、name 等数据成员，由 Animal 类公有派生出鱼 (Fish) 类、陆地动物 (TerrestrialAnimal) 类。 Fish 类有鳍 (Fim) 属性， TerrestrialAnimal 类有腿 (Leg) 属性。从 Fish 和 TerrestrialAnimal 公有派生出爬行动 物 (Reptile) 类。

在继承过程中，把 Animal 设置为虚基类。
Animal类的构造函数中输出信息：cout << "Animal Constructor" << endl;
Fish类的构造函数中输出信息：cout << "Fish Constructor" << endl;
TerrestrialAnimal类的构造函数中输出信息：cout << "TerrestrialAnimal Constructor" << endl;
Reptile类的构造函数中输出信息：cout << "Reptile Constructor" << endl;
Reptile类包含如下成员函数：
void Reptile::Print(){
cout << "Reptile Age:" << Age << endl;
}

Answer 1

类的构造函数不能是虚函数，而且没有返回值。你写了两种构造函数，带参数的构造和默认构造。默认构造函数要写成：

Animal()
{
    cout << "Animal Constructor" << endl;
}

然后，题目要求构造函数要有输出，所以带参数的构造函数应该也需要输出：

Animal(unsigned int age,double weight,string name)
        {
            Age=age;
            Weight=weight; 
            Name=name;
            cout << "Animal Constructor" << endl;
        }

按这样把所有类都改一下。
还有就是52行，在类里实现成员函数的时候不需要 :: 操作符，在类中声明类外实现才需要加，可以直接写成

    void Print()
    {
        cout << "Reptile Age:" << Age << endl;
    }