输入10个数，输出它们的平均值及大于平均值的数。

Question

请速答，本人实在不行不会，特来请教各路人才指点一二，本人万分感谢。

Answer 1

#include <stdio.h>

int main()
{
    int num[10] = { 0 }, sum = 0;
    double average = 0;

    printf("输入10个数字：");
    for (int i = 0; i < 10; i++)
    {
        scanf("%d", &num[i]);
        sum += num[i];
    }
    printf("平均值为%lf\n", average = (double)sum / 10.0);
    printf("大于平均值的数为：");
    for (int i = 0; i < 10; i++)
    {
        if(num[i] > average)
            printf("%d ", num[i]);
    }

}