DES加密字符串并转换为十六进制

Question

I am trying to find a way in PHP that can encrypt a string in hex using DES algorithm. The result I need should be exactly like this page.

All PHP codes that I tried gave different results than what I got in that page. I tried this code for example:

<?php
function Encrypt($data, $key)
{    
  $encData = mcrypt_encrypt('tripledes', $key, $data, 'ecb');
  return $encData;
}
echo strtoupper(bin2hex(Encrypt("12341234", "1100000120140129")));
?>

The result was: 0D54E1C0B08DCB90. While in this link, the result is: 4DC7D8B78F0F33A3.

Note that 31313030303030313230313430313239 is 1100000120140129 in hex and 3132333431323334 is 12341234 in hex.

Answer 1

This problem seems to be caused by the way PHP reads keys and data when you supply them as strings. Solve this problem by using code such as the following:

$key = pack('H*', "0123456789abcdef"); // this correctly maps hex to bytes
$data = pack('H*', "0123456789abcdef");
echo bin2hex(mcrypt_encrypt(MCRYPT_DES, $key, $data, MCRYPT_MODE_ECB));

This outputs 56cc09e7cfdc4cef which matches the DES calculator (proof).

---

For those interested, I also used the following Java code to deduce what was going on. This prints the same result as the PHP:

SecretKey key = new SecretKeySpec(new byte[8], "DES");

Cipher cipher = Cipher.getInstance("DES/ECB/NoPadding");
cipher.init(Cipher.ENCRYPT_MODE, key);

System.out.println(DatatypeConverter.printHexBinary(cipher
    .doFinal(new byte[8])));