你能看出这条代码为什么不能输出吗？

Question

#include<stdio.h>
#define N 5
void copy2(double (*parr2)[2] , double(*receive2)[2]);
int main(void)
{
    const double arr[N][2] = 
    {
        {1.2 , 2.2} , {3.3,4.4} ,
        {5.5 , 6.6} , {7.7,8.8} , {9.9 , 1.1}
    };
    double target2[N][2];

    printf("copy2 is :\n");
    copy2(target2 , arr);
    
    return 0;
}
void copy2(double (*parr2)[2] , double(*receive2)[2])
{
    int x , y;
    for(x = 0 ; x < N ; x++)
    {
        for(y = 0 ; y < 2 ; y++)
        {
            parr2[x][y] = receive2[x][y];
            if(x >= 1 && x<= 3)
                printf("%4g",parr2[x][y]);
            if(y = 1 && x >= 1 && x<= 3)
                printf("\n");
        }
    }
}

为什么这条代码卡着输出不了啊？看了好久不知道哪里有bug？请求帮忙一下，刚入门技术不行 T T

Answer 1

28行
if(y == 1 && x >= 1 && x<= 3) //y==1