dongyun65343 2016-11-16 06:21
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如何使用php mail()在收件箱邮件中显示邮件发件人个人资料图片和标题?

I have a problem when sending an email with PHP The problem is my email title and from variable is blank

Screenshot of my email:

enter image description here

I use my work email address to send an email. My script is like this

public static function header($from, $cc = false, $replyTO = null) {
    $headers = "From: " . $from . "
";
    if ($replyTO) {
    $headers .= "Reply-to: ". $replyTO ."
"; }
    if ($cc) {
    $headers .= "CC: ". $cc ."
"; }
    $headers .= "MIME-Version: 1.0
";
    $headers .= "Content-Type: text/html; charset=ISO-8859-1
";

    return $headers;
}

public static function top() {
    return file_get_contents('email/top.php');
}

public static function footer() {
    return file_get_contents('email/bottom.php');;
}

public static function output( $url ) {

    $message = self::top();
    $message .= $url;
    $message .= self::footer();

    return $message;
}

public static function send($from, $to, $subject, $content) {
    if ( mail($to, $subject, $content, self::header($from)) ) {
        return true;
    }

    return false;
}

Any solution ? thank you in advance

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2条回答 默认 最新

  • dsaeyrq451928 2016-11-16 06:30
    关注

    For From name:

    Try the following:

    public static function header($from,$sender_name='', $cc = false, $replyTO = null) {
        $headers = "From: ".$sender_name."<" . $from . "> 
    ";
        if ($replyTO) {
        $headers .= "Reply-to: ". $replyTO ."
    "; }
        if ($cc) {
        $headers .= "CC: ". $cc ."
    "; }
        $headers .= "MIME-Version: 1.0
    ";
        $headers .= "Content-Type: text/html; charset=ISO-8859-1
    ";
    
        return $headers;
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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