char s[] = {'A', 'B', 'C', '2', '1', '0', '\0', 'A'};
int count = 0;
for (int i = 0; s[i] != '\0', i++;)
count++;
printf("%d\n", count); //结果1 =0
count = 0;
for (int i = 0; s[i] != '\0'; i++)
count++;
printf("\n%d", count);//结果2 = 6
for (int i = 0; s[i] != '\0', i++;)问过人说是错的,但为什么可以运行出count=0
for (int i = 0; s[i] != '\0'; i++)
if (s[i] == 'A')
count++;
printf("\n%d", count); //结果3 = 1
如果char s[] = {'A', 'B', 'C', '2' , '1', '0', 'A'};
结果3会变成2.
这里的意思是“如果s[i]=A,count+1”吗?如果是这样,为什么count=1而不是2,因为在'\0'处结束运算,然后再重新算,所以是1,没有\0就是2?