使用jQuery在页面上提交1个Ajax表单，其中包含几个独特的表单

Question

I have a Bootstrap page that is dynamically created using PHP, and on the page there are 25+ forms that are used to edit records.

The form submits to the server using jQuery Ajax script which works as expected on the first form, but when the second form is edited and submitted it submits form 1 and 2, and when I go to form 3 it will submit forms 1, 2, and 3 Here is the HTML:

<tr id="375987">
  <td width="20%">audio controls to play wav file</td>
  <td width="80%">
    <div class="form-group">
      <form id="375987">
        <textarea class="form-control" id="rec_txt" name="rec_txt" rows="4">There is text from the Database</textarea>
        <input type="text" id="event_num" name="event_num" value="" />

        <button type="submit" id="correct_stt" class="btn btn-outline-success my-2 my-sm-0" OnClick="update_stt()">Edit</button>
        <input type="hidden" id="rec_id" name="rec_id" value="375987" />
        <input type="hidden" name="act" value="correct_stt" />
      </form>
    </div>
  </td>
  <td>
    <a href="#" class="btn btn-primary a-btn-slide-text" onClick="hiderow('375987')">
      <span class="glyphicon glyphicon-remove" aria-hidden="true"></span>
      <span><strong>Hide</strong></span>
    </a>
  </td>
</tr>

<!-- 25+ forms     ..... -->

And here is the Java:

function update_stt() {
  var url = "function_ajax.php"; // the script where you handle the form input.
  $('form[id]').on('submit', function(e) {
    $.ajax({
      type: 'POST',
      url: url,
      data: $(this).serialize(),
      success: function(data) {
        console.log('Submission was successful.');
        console.log(data);
        $(e.target).closest('tr').children('td,th').css('background-color', '#000');
      },
      error: function(data) {
        console.log('An error occurred.');
        console.log(data);
      },
    });
    e.preventDefault();
  });
}

How can I identify only the id of the form that I want submitted, or submit only the form on that row?

Answer 1

You can give id to forms and use

$('#formid').submit();

in your case

$('#375987').submit();

But that id is used by your tr div too. You should consider using id for form only