代码:
#include <iostream>
#include <windows.h>
#include <ctime>
#include <cstdlib>
#include <stdio.h>
#include <fstream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <bits/stdc++.h>
#include <set>
#include <map>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <conio.h>
using namespace std ;
void xinghao()
{
cout << "*****************" << endl ;
}
static string time()
{
time_t t = time(NULL) ;
char ch[64] = {0} ;
strftime(ch , sizeof(ch) -1 , "%Y-%m-%d %H:%M:%S" , localtime(&t)) ;
return ch ;
}
int main()
{
ofstream log("CHJ.log" , std::ios::out | std::ios::app) ;
log << "[" << time() << "]" << "opened" << endl ;
log << "[" << time() << "]" << "loading" << endl ;
int a = 0 ;
int times ;
ifstream dat("times.dat" , ios::in) ;
dat >> times ;
dat.close() ;
ofstream data("times.dat" , ios::trunc | ios::out) ;
if(times >= 1 && times < 4000000)
{
times++ ;
data << times ;
}
else
{
data << "1" ;
}
data.close() ;
log << "[" << time() << "]" << "the load was complete" << endl ;
log << "[" << time() << "]" << "this procedure is from MCyouwan" << endl ;
log << "[" << time() << "]" << "this procedure's version is rd-1,open times:" << times << endl ;
xinghao() ;
cout << "吃鸡游戏" << endl << "作者:MCyouwan" << endl ;
xinghao() ;
cout << "打开次数:" << times << endl ;
其中,输出的“打开次数”为4633604(初次),并且times.dat显示也为4633604。并且往后打开会不断+1(在这个数字的基础上)。
理想状态下应为:
初次打开:“打开次数”为1,times.dat为1
2次打开:“打开次数”为2,times.dat为2
以此类推
不知道为什么,它总会自动生成一个不知道是什么的数字,但程序无报错
求解答