在1个数据库列中更新多个结果

Question

Trying to update multiple results in 1 database column first need to get previous values than update with new so far i wrote this query but it's not working see code query & current results

Code

<?php
include( $_SERVER['DOCUMENT_ROOT'] . '/config.php' ); $mysqli = $link;

  $user_pages = mysqli_query($mysqli,"SELECT actual_grand_total FROM user_pages"); 
  $actual_grand_total = $user_pages/100;
  $query1 = mysqli_query($mysqli,"update user_pages set actual_grand_total=($actual_grand_total)");
  $user_pages = mysqli_query($mysqli,"SELECT grand_total FROM user_pages"); 
  $grand_total = $user_pages/100;
  $query2 = mysqli_query($mysqli,"update user_pages set grand_total=($grand_total)");

?>

database table "user_pages"

actual_grand_total | grand_total
------------------   -----------
       1000             750     
       5000             500     
       7500             750     

I am getting those wrong results

    actual_grand_total | grand_total
    ------------------   -----------
           1.000             1.000     
           1.000             1.000     
           1.000             1.000  

expected results

 actual_grand_total | grand_total
    ------------------   -----------
           10             7.5     
           50             5     
           75             7.5     

can someone correct me ... i want to update current results dividing by 100

Answer 1

you could do directly and using a single query

   update user_pages 
   set  actual_grand_total = actual_grand_total/100 ,  
        grand_total = grand_total/100