简单的jQuery + PHP无法正常工作

Question

I have the following code in my javascript:

$.ajax({
    url : 'update_data.php',
    type : 'POST',
    data : 'asdfasd', //d,
    success : function(response){
        console.log(response);
    },
    error: function(jqXHR, textStatus, errorThrown){
        console.log('jqXHR.responseText:  ' + jqXHR.responseText);
        console.log('jqXHR.responseXML :  ' + jqXHR.responseXML);
        console.log('textStatus:   ' +  textStatus);
        console.log('errorThrown:   ' + errorThrown);
    },
    dataType : 'text'
});

Here is my 'update_data.php' :

<?php
    echo json_encode($_POST);
    if (isset($_POST['data'])){
        echo "here!";
    } else {
        echo "failed jquery";
    }
?>

When I run the Ajax method, I get the following response in my console:

[]failed jquery

meaning update_data.php didn't get any POST request. '[]' is from json_econd($_POST), and 'failed jquery' is from the if/else.

What am I doing wrong?

Answer 1

you need to pass data as below

 data : {'data':'asdfasd'},

if want to pass multiple parameters then

data : {'data':'asdfasd','param1':'value','param2':'value'},

or submit data of form

data : $( "formselector" ).serialize(),

data parameter in ajax

Type: PlainObject or String or Array Data to be sent to the server. It is converted to a query string, if not already a string. It's appended to the url for GET-requests. See processData option to prevent this automatic processing. Object must be Key/Value pairs. If value is an Array, jQuery serializes multiple values with same key based on the value of the traditional setting (described below).

Read more about jquery ajax parameters HERE