dongzhong5833 2017-03-26 03:44 采纳率: 0%
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显示给定MySQL数据库中的所有表

I'm trying to show all tables within a given MySQL database with php. I'm very new to all this though and can't find a solution for it. Keeps giving an error 'no found file or directory'.

Anyone who can point out my mistakes here please? Much appreciated!

<?php include "../inc/dbinfo.inc"; ?>
<html>
<body>
<h2>LIST TABLES FROM DATABASE</h2>
<?php

// Create connection
$conn = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);

// Check connection
if ($conn->connect_error) {
    die("Connection with the database failed: </br>" . $conn->connect_error);
}
echo "Connection established with the database! </br>";

// SQL to show tables

$sql = "SHOW TABLES FROM paperlessdb";
$result = mysql_query($sql);

if (!$result) {
    echo "Database error, could not list tables.
</br>";
    echo 'MySQL error: ' . mysql_error();
    exit;
}

while ($row = mysql_fetch_row($result)) {
    echo "- {$row[0]}
 </br>";
}

mysql_free_result($result);
?>
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3条回答 默认 最新

  • doufu7464 2017-03-26 04:09
    关注

    First make up your mind, either use mysqli procedural or object orientated. Not a combination of both because its confusing. To avoid that all together use pdo instead.

    Now properly connect to the database, you can select the database when connecting to it automatically:

    const DB_DATABASE = 'paperlessdb';
    
    $conn = new mysqli(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_DATABASE);
    
    // Check connection
    if ($conn->connect_error) {
        die("Connection with the database failed: </br>" . $conn->connect_error);
    }
    
    if($result = $conn->query('SHOW TABLES')){
      while($row = $conn->fetch_array($result)){
        $tables[] = $row[0];
      }
    }
    
    print_r($tables);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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