douhu1990 2011-03-05 10:24
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PHP Json编码一个数组

Im a newbie in PHP (also JSON for that matter) but I am not sure/confident of the format of the json data i have. I am converting a mysql into json for use in another application, and the format i am getting is as follows:

    [
     {
        "category":
        {
            "catId":"1",
            "categoryName":"BABY FOOD",
            "categoryNotes":"ONLY baby food varieties which have been listed below should be used. However if your doctor or pediatrician requires a specific diet please contact your Rabbi for further advice."
        }
    },
    {
        "category":
        {
            "catId":"2",
            "categoryName":"BAKING INGREDIENTS",
            "categoryNotes":""
        }
    },
    {
        "category":
        {
            "catId":"131",
            "categoryName":"BEER",
            "categoryNotes":"See Alcoholic Drinks"
        }
    },
    {
        "category":
        {
            "catId":"4",
            "categoryName":"BEVERAGES - Powdered",
            "categoryNotes":""
        }
    },
    {
        "category":
        {
            "catId":"5",
            "categoryName":"BISCUITS",
            "categoryNotes":"Locally produced biscuits usually contain fats, oils or improvers of non-kosher origin.  There is a very large range of Israeli, South African and American kosher biscuits available locally. Even these imported biscuits and crackers (including Israeli produced goods) should only be used if marked with a reliable Rabbinic Hechsher. A 'K' on the packet alone is insufficient. Please note which products are dairy or pareve."
        }
    },
    {
        "category":
        {
            "catId":"6",
            "categoryName":"BREAD AND BAKERY GOODS",
            "categoryNotes":"Bread usually contains or comes in contact with Non-Kosher oils, fats or improvers and cannot be accepted as kosher without thorough investigation and subsequent authorisation"
        }
    },
    {
        "category":
        {
            "catId":"7",
            "categoryName":"BREAD\/CORN\/RICE CRUMBS",
            "categoryNotes":""
        }
    },
    {
        "category":
        {
            "catId":"8",
            "categoryName":"BUTTER AND DAIRY BLENDS",
            "categoryNotes":"Soft butters, butter spreads & dairy blends are NOT ACCEPTABLE unless specifically listed. Butter made from whey cream is NOT ACCEPTABLE unless produced under Rabbinic supervision"
        }
    },
    {
        "category":
        {
            "catId":"9",
            "categoryName":"BUTTERMILK and LEBEN ",
            "categoryNotes":""
        }
    },
    {
        "category":
        {
            "catId":"10",
            "categoryName":"CAKES & CAKE SHOPS",
            "categoryNotes":"Cakes and cake mixes usually contain Non-Kosher ingredients, and must only be used if they are produced under supervision <br\/> Cakes bought in a Non-Kosher cake shop, even if containing only kosher ingredients are NOT ACCEPTABLE because of the Non-Kosher utensils used in their preparation"
        }
    },
    {
        "category":
        {
            "catId":"11",
            "categoryName":"CEREALS ",
            "categoryNotes":""
        }
    },
    ...
]

and so forth.

Now I am not sure if this is the right format, but my code to generate this is as follows:

            <?php


            /* soak in the passed variable or set our own */
            // $approved_prod_date = $_GET['date'];



            $link = mysql_connect('localhost','root','broncos') or die('Cannot connect to the DB');
            mysql_select_db('iKosher',$link) or die('Cannot select the DB');

            /* grab the categories from the db */
            $query=  "SELECT c.id as catId, c.name as categoryName,     c.notes as categoryNotes
                FROM        cat c
                WHERE       1=1
";


            if(isset($_GET['catid']) && intval($_GET['catid'])) {
                $query.="AND c.id = ";
                $query.= $_GET['catid'];
            }   


            if(isset($_GET['startIndex']) && intval($_GET['startIndex'])) {
                if(isset($_GET['numItems']) && intval($_GET['numItems'])) {
                    $query .= "
LIMIT ";
                    $query .= $_GET['startIndex'];
                    $query .= ","; 
                    $query .= $_GET['numItems'];
                }
            }




             // $query = "SELECT post_title, guid FROM wp_posts WHERE post_author = $user_id AND post_status = 'publish' ORDER BY ID DESC LIMIT $number_of_posts";
            $result = mysql_query($query,$link) or die('Errant query:  '.$query);
            $num=mysql_numrows($result);


            /* create one master array of the records */
              $categories = array();
              if($num) {
                while($category = mysql_fetch_assoc($result)) {
                  $categories[] = array('category'=>$category);
                }
              }
                header('Content-type: application/json');
                echo json_encode($categories);
            ?>

Based on my code, am i doing this right? Is the array converted correctly into JSON?

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2条回答 默认 最新

  • du13932014807 2011-03-05 10:27
    关注

    json_encode() will produce valid JSON. If necessary, you can verify this for yourself by copy-and-pasting the JSON output into an online validator like the one at http://www.jsonlint.com/

    If you're not sure if your data is being placing into the array with the correct organization, that's another matter. But given a valid PHP array/object/pretty much whatever, json_encode() will produce it encoded properly in the JSON format.

    EDIT: Inside your while loop, this code:

            while($category = mysql_fetch_assoc($result)) {
              $categories[] = array('category'=>$category);
            }
    

    Builds an array that looks like this: ("category" => [$catId, $categoryName, etc.], "category" => [$catId, $categoryName, etc], and so on) I think you'd be better off (and happier with the JSON produced) if you changed it to:

            while($category = mysql_fetch_assoc($result)) {
              $categories[] = $category;
            }
    

    The original code is adding each and every category to the $categories array with the same "category" key. But since this key is duplicated for each category, it serves no real purpose.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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