从目录中读取文件名

Question

I want to read html file name from directory without any database. I have a code and its working properly, but two blank name it is giving, while I have only 4 file in directory.

<?php
 if (is_dir('dir')) {
if ($dh = opendir('dir')) {
    while (($file = readdir($dh)) !== false) {
        echo "filename:".$file."<br />";
    }
}
}?>

I have 4 html file and output should be:

filename:aaaaaa kjnnk_13.html
filename:aaaaaa kjnnk_2.html
filename:aaaaaa kjnnk_6.html
filename:aaaaaa kjnnk_9.html

But I found 2 extra filename:

filename:.
filename:..
filename:aaaaaa kjnnk_13.html
filename:aaaaaa kjnnk_2.html
filename:aaaaaa kjnnk_6.html
filename:aaaaaa kjnnk_9.html

Please help

Answer 1

. is for current dir .. is for one directory up

When using readdir you will get those 2 extra.

I prefer using glob(). That function lets you filter for html files only too

<?php
   $files = glob('dir/*html');
   foreach($files as $file) {
       echo "filename:".$file."<br />";
   }
?>