关于#密码强度#的问题，如何解决？

Question

这提交了怎么会这样啊大家

#include<stdio.h>
int main(void)
{
int n;
char pass_wd[100];
int upper_case;
int lower_case;
int num;
int symbol;

scanf("%d",&n);

for(int i=0;i<n;i++)
{
  for(int j=0;j<+100;j++)
  pass_wd[i]=getchar();
  if( strlen(pass_wd)<8)
  continue;
  for(i=0;i<strlen(pass_wd);i++)
  {
      if(pass_wd[i]>='a'&&pass_wd<='z')
      lower_case++;
      else if(pass_wd[i]>='A'&&pass_wd<='Z')
      upper_case++;
      else if(pass_wd[i]>='0'&&pass_wd<='9')
      num++;
      else if(pass_wd[i]>=33&&pass_wd[i]<=126)
      symbol++;
  }
    if((upper_case==0&&lower_case==0)||(upper_case==0&&num==0)||(upper_case==0&&symbol==0)||(lower_case==0&&num==0)||(lower_case==0&&symbol==0)||(num==0&&symbol==0))
printf("Weak");
    else if((upper_case==0&&lower_case==0&&num==0)||(upper_case==0&&lower_case==0&&symbol==0)||(lower_case==0&&num==0&&symbol==0)||(upper_case==0&&num==0&&symbol==0))
printf("Weak");
    else printf("Strong");
}
return 0;
}

Answer 1

直接(upper_case?1:0) + (lowerr_case?1:0) + (num?1:0) + (symbol?1:0) >= 3 即可