doutang9037 2017-11-30 07:40 采纳率: 100%
浏览 43
已采纳

根据用户选择最后一个学习(最大)课程

What I am doing?

I am displaying the user according to there studied. I want to fetch the last course studied by each user.

Problem?

I am not getting the last course name according to last studied course. I am getting the first course name.(java) but i want (oracle) as last studied course by user.

User Table

user_id | Name
====================
1       | Zishan                                          
2       | Ellen

Course Table

course_id | course_name | user_id | course_year 
==================================================
   1      |  java       | 1       | 2015   
   2      |  C++        | 1       | 2017
   3      |  oracle     | 1       | 2016
   4      |  dot net    | 2       | 2016

Result Table

Name    | last_course_name | last_course_year
============================================
Zishan  | java             | 2017
Ellen   | dot net          | 2016

Expected Result

Name    | last_course_name | last_course_year
============================================
Zishan  | C++              | 2017
Ellen   | dot net          | 2016

Query

SELECT `u`.`name`, MAX(`c`.`course_year`) as last_course_year , `c`.`course_name` as last_course_name 
FROM `user` as `u`
LEFT OUTER JOIN `course` as `c` ON `u`.`id` = `c`.`user_id`
GROUP BY `u`.`id`

Active Record Query:

$this->db->select('u.name','c.course_name as last_course_name');
$this->db->select_max('c.course_year as last_course_year'); 
$this->db->from('user as u');
$this->db->join('course as c', 'u.id = c.user_id', 'left');
$this->db->join('course as c1', 'c.user_id = c1.user_id', 'left outer');    
$this->db->where('c1.user_id IS NULL', null, false); 
$this->db->group_by('u.id');
$user_couse_data_query = $this->db->get();
  • 写回答

4条回答 默认 最新

  • duanchao4445 2017-11-30 08:01
    关注

    Here you go to the latest row from course table for each student

    SELECT `u`.`name`, `c`.`course_name` as last_course_name ,c.course_year
    FROM `user` as `u`
    LEFT JOIN `course` as `c` ON `u`.`id` = `c`.`user_id`
    LEFT JOIN `course` as `c1` ON `c`.`user_id` = `c1`.`user_id` AND  `c`.`course_year` < `c1`.`course_year`
    WHERE `c1`.`user_id` is null
    

    Demo

    Note it may return multiple courses if they share same year

    Equivalent active record query will be something like

    $this->db->select('u.name','c.course_name as last_course_name','c.course_year as last_course_year');
    $this->db->from('user as u');
    $this->db->join('course as c', 'u.id = c.user_id', 'left');
    $this->db->join('course as c1', 'c.user_id = c1.user_id AND c.course_year < c1.course_year', 'left');    
    $this->db->where('c1.user_id IS NULL', null, false); 
    $user_couse_data_query = $this->db->get();
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(3条)

报告相同问题?

悬赏问题

  • ¥15 如何绘制动力学系统的相图
  • ¥15 对接wps接口实现获取元数据
  • ¥20 给自己本科IT专业毕业的妹m找个实习工作
  • ¥15 用友U8:向一个无法连接的网络尝试了一个套接字操作,如何解决?
  • ¥30 我的代码按理说完成了模型的搭建、训练、验证测试等工作(标签-网络|关键词-变化检测)
  • ¥50 mac mini外接显示器 画质字体模糊
  • ¥15 TLS1.2协议通信解密
  • ¥40 图书信息管理系统程序编写
  • ¥20 Qcustomplot缩小曲线形状问题
  • ¥15 企业资源规划ERP沙盘模拟