JSON漂亮的打印，而不使用PHP中的json_decode

Question

For example i have json strings like this ( from the first place ). And It's not formatted.

{"data":[{"id":"14","memo_kondisi":"Kekurangan pekerjaan","total_row":"5","nilai_temuan":"1.000.000","data_sebab":[{"id":"15","id_sebab":"","id_sub_sebab":"","memo_sebab":"coba","data_rekomendasi":[{"id":"25","id_rekomendasi":"10","id_sub_rekomendasi":"","id_s_sub_rekomendasi":"","nilai_rekomendasi":"0"},{"id":"26","id_rekomendasi":"10","id_sub_rekomendasi":"","id_s_sub_rekomendasi":"","nilai_rekomendasi":"0"},{"id":"31","id_rekomendasi":"10","id_sub_rekomendasi":"","id_s_sub_rekomendasi":"","nilai_rekomendasi":"0"}]},{"id":"16","id_sebab":"","id_sub_sebab":"","memo_sebab":"coba","data_rekomendasi":[{"id":"34","id_rekomendasi":"10","id_sub_rekomendasi":"","id_s_sub_rekomendasi":"","nilai_rekomendasi":"0"},{"id":"35","id_rekomendasi":"10","id_sub_rekomendasi":"","id_s_sub_rekomendasi":"","nilai_rekomendasi":"0"}]}]},{"id":"15","memo_kondisi":"Kekurangan pekerjaan","total_row":"2","nilai_temuan":"1.000.000","data_sebab":[{"id":"5","id_sebab":"","id_sub_sebab":"","memo_sebab":"coba","data_rekomendasi":[]},{"id":"10","id_sebab":"","id_sub_sebab":"","memo_sebab":"coba","data_rekomendasi":[]}]},{"id":"16","memo_kondisi":"","total_row":"2","nilai_temuan":"0","data_sebab":[{"id":"9","id_sebab":"","id_sub_sebab":"","memo_sebab":"coba","data_rekomendasi":[]},{"id":"12","id_sebab":"","id_sub_sebab":"","memo_sebab":"coba","data_rekomendasi":[]}]}]}

I see some similar question that you have to use json_decode and i have to encode again and using json_encode($json,JSON_PRETTY_PRINT)

Is there a way for make json readable without decode the JSON first and encode it again in PHP ?

Note : I expect the result is still in JSON

Answer 1

Only a parser can understand the JSON, so you can either do what you proposed or write your own parser. If you have access to the origin of the JSON, make it pretty in the first place.