dongxi7609 2014-06-06 06:02 采纳率: 0%
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Ajax从PHP函数中获取错误或成功消息

I'm post data to a php function using JSON post. I want to receive two different type of responses, success and error. For example, the following function:

function some_function(){

    if ($error){
        echo "some error";
        exit;
    } else {    
        echo "everything is ok"
        exit;
    }

}

In this case, both messages will be returned as success. How can I make the error message return to the error function in the ajax? Here's the ajax code:

jQuery.ajax({

    url: '<?php echo $url; ?>',
    data: response,
    dataType: 'JSON',
    type: 'POST',
    success:function(data){
        console.log(data);
    },
    error: function(data, errorThrown){
        console.log(errorThrown);
    }

});
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4条回答 默认 最新

  • douewei1665 2014-06-06 06:11
    关注

    Try this one:

    jQuery.ajax({
    
        url: '<?php echo $url; ?>',
        data: response,
        dataType: 'JSON',
        type: 'POST',
        success:function(data){
            if(data['error']){
               alert(data['error']);
              }else{
                 alert(data['success']);
              }
        },
        error: function(data, errorThrown){
            console.log(errorThrown);
        }
    
    });
    

    On PHP page:

    function some_function(){
    
            if ($error){
                $msg = array("error"=>"some error";
            } else {    
                $msg = array("success"=>"everything is ok");
            }
           echo json_encode($msg);die;
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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