dtlygweb2017 2017-04-13 17:55
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PHP正则表达式如何捕获末尾没有字母的浮点数

I'm using preg_match_all and I want to capture the floating point numbers that do not have a letter following them.

For example

-20.4a 110b 139 31c 10.4

Desired

[0] => Array
    (
        [0] => 139
        [1] => 10.4
    )

I've tried was able do to the opposite using this pattern:

/\d+(.\d+)?(?=[a-z])/i

which captures the numbers with letters that you can see in this demo. But I can't figure out how to capture the numbers that have no trailing letters.

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3条回答 默认 最新

  • doubi8965 2017-04-13 17:59
    关注

    You can use this regex with a positive lookahead:

    [+-]?\b\d*\.?\d+(?=\h|$)
    

    RegEx Demo

    (?=\h|$) asserts presence of a horizontal white space or end of line after matched number.

    Alternatively you can use this regex with a possessive quantifier:

    [+-]?\b\d*\.?\d++(?![.a-zA-Z])
    

    RegEx Demo 2

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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