dt2002 2010-02-02 14:17
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JQUERY AJAX LOAD函数错误

I loaded a second.php file in first.php using jquery ajax load function

$(".divclass").click(function(){ $("#divid").load('second.php', { id : $(this).attr('id') }); // alert("view Clicked"); });

the second.php loaded second php content in first.php file success.

but second.php contains some jquery function... in second.php

$(document).ready(function(){ alert("second document jquery"); });

this not working... and Back this back javascript also not working when load in first.php but both working when directly calling second.php

what to do

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3条回答 默认 最新

  • doutuo3575 2010-02-02 14:24
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    Your second file — which I presume is a fragment of HTML and not a complete document — is not going to get a "ready" event, because you're just modifying the DOM. If you need some embedded Javascript to run, just put it directly in a tag at the end of the fragment:

    <div id='stuff'>
      <!-- ... --->
    </div>
    <script>
      alert("Hi I have just been loaded");
    </script>
    

    jQuery will make sure that the Javascript block runs when the fragment is added to the DOM.

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