PHP 7.2 + Laravel 5.8：调用Trait中定义的父方法，该方法在使用此特征的类中调用父方法时被覆盖

Question

It may be hard to explain this case via title so let me put it here.

I had to use Laravel Boilerplate. It uses UUIDs for models. It has a trait that when User model is being created, it adds UUID.

protected static function boot() // this is in the trait
{
    parent::boot();

    static::creating(function ($model) {
        $model->{$model->getUuidName()} = PackageUuid::generate(4)->string;
    });
}

My Eloquent User uses this trait. Everything was working but one day I had to add global scope to User so I defined in the User class:

protected static function boot()
{
    parent::boot();

    static::addGlobalScope(new UserScopeSalesContactAdmin());
}

I totally missed that. Now my global scope works but UUID is ignored. I obviously know why this happens. I'm not the author of the Boilerplate and I would architecture this in a different way but it's a nice educational case hence my question:

How can I change my code the way that both my global scope works as well as UUID? I could simply move my addGlobalScope to the trait but it's obviously stupid idea as scope has nothing to do with UUID hence it violates the OOP rule.

edit:

I did other way around: I copied:

static::creating(function ($model) {
     $model->{$model->getUuidName()} = PackageUuid::generate(4)->string;
});

to the boot method in the User but still I consider this as a duplication…

Answer 1

You can write your own trait. But instead of boot() define boot<TraitName>():

trait HasUuid
{
    protected static function bootHasUuid()
    {
        static::creating(function ($model) {
            $model->{$model->getUuidName()} = PackageUuid::generate(4)->string; 
        });
    }
}

This way you don't need to override boot().

Laravel will call the special boot method of traits based on the naming scheme described above. It's just not well documented functionality...