duanhuang4841 2018-03-04 12:28
浏览 73

在php中实现链表 - 这是安全的构造吗?

Here is an implementation of linked list. It's OK, it's working. But there are few lines that bother me (comments inside method are mine):

//insertion at the start of linklist
public function insertFirst($data)
{
    $link = new ListNode($data);     // create local variable
    $link->next = $this->firstNode;
    $this->firstNode = &$link;       // and remember the reference to it in $this->firstNode

Edit: Let me analyse this method line by line: L1. We create a local variable: $link. L2. Doesn't matter. L3. In 'firstNode' property we save the reference to local variable.

OK, all clear. But at the end of this method the local variable ($link) will be destroyed. So in 'firstNode' we have a reference to non-existent variable. The place in memory where $link variable was stored is free now. PHP can store there something new. Isn't it?

  • 写回答

0条回答 默认 最新

    报告相同问题?

    悬赏问题

    • ¥15 如何在scanpy上做差异基因和通路富集?
    • ¥20 关于#硬件工程#的问题,请各位专家解答!
    • ¥15 关于#matlab#的问题:期望的系统闭环传递函数为G(s)=wn^2/s^2+2¢wn+wn^2阻尼系数¢=0.707,使系统具有较小的超调量
    • ¥15 FLUENT如何实现在堆积颗粒的上表面加载高斯热源
    • ¥30 截图中的mathematics程序转换成matlab
    • ¥15 动力学代码报错,维度不匹配
    • ¥15 Power query添加列问题
    • ¥50 Kubernetes&Fission&Eleasticsearch
    • ¥15 報錯:Person is not mapped,如何解決?
    • ¥15 c++头文件不能识别CDialog