webservice接口方法中怎么读取request流，得到in这个流侯总是异常关闭

Question

@Resource
private WebServiceContext wsContext;

public IEOMS2EOSImp() {

}

// @Override
public String replyWorkSheet(int sheetType, int serviceType){
// TODO Auto-generated method stub
MessageContext mc = wsContext.getMessageContext();
logger.debug("mc:::::"+mc.toString());
//

    //获取HttpServletRequest对象
    HttpServletRequest request = (HttpServletRequest)(mc.get(MessageContext.SERVLET_REQUEST));
    logger.debug("request::::"+request.toString());
    //记录时间
    Date time=new Date();

    try {
        request.setCharacterEncoding(encode);
        String ip = request.getRemoteAddr();
        logger.debug("ip:::"+ip);
        //跳过Header的校验
        //以字节流方式取参数
        BufferedReader in = new BufferedReader(new InputStreamReader(request.getInputStream(),encode));
        logger.debug("in:::"+in.toString());
        StringBuffer sb = new StringBuffer();
        StringBuffer sb2 = new StringBuffer();
        String tmp = "";

        while ((tmp = in.readLine()) != null){
          sb.append(tmp).append("\n");
          sb2.append(tmp);
        }

          String reqParamString = sb.toString().trim();
        logger.debug("\n"+reqParamString);
    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        logger.error("UnsupportedEncodingException", e);
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        logger.error("IOEXCEPTION", e);
    }*/

    return "回调成功12345";
}

Answer 1

https://blog.csdn.net/m0_38053538/article/details/80656012