php include语句

Question

I'm working on my first website using php. I came up with a good way, or so I thought, to deal with including the css sheet depending on where I am. For example, I have a form that I submit to with this code:

 $root = '../';


 function died($error) 
 {
  include '../includes/header.php';
  echo "We are very sorry, but there were error(s) found with the form your submitted. ";
  echo "These errors appear below.<br /><br />";
  echo $error."<br /><br />";
  echo "Please go back and fix these errors.<br /><br />";
  include '../includes/footer.php';
  die();
 }

I set the variable $root to have "../" and then here is the relevant part of header.php:

<link href="<?php echo $root;?>styles/styles.css" rel="stylesheet" type="text/css" />

I would think that it would put in "../" in front of styles, but it doesn't put anything. Why doesn't this work?

Thanks!

Answer 1

You can make the path to your CSS file absolute:

<link href="/styles/styles.css" rel="stylesheet" type="text/css" />

Prefixing a URL with a forward slash (/) will make the URL relative to your site's root. The above example would reference something like http://example.com/styles/styles.css. This way, you can put all your CSS in a folder at the root of your site and not have to worry about the path at all.