drhg24275 2018-05-14 06:36
浏览 157

通过URL传递参数到php,但php没有得到它,为什么?

I create the table and use ajax to pass data.

This is my ajax part, I put the parameter in URL, but php code doesn't read it.

$.ajax({
        type:"POST",
        url:"system_setting.php?p=add",
        data:"username="+username+"&password="+password+"&nickname="+nickname+"&authority="+authority,
        success:function(data){
            viewData();
        }
    });

I use $page=isset($_GET['p'])?$_GET['p']:''; to judgment parameter, but it doesn't read. Please teach me how should I do, thank you.

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4条回答 默认 最新

  • dtcwehta624485 2018-05-14 06:41
    关注

    Use POST instead and add p=add in data instead url

    $.ajax({
        type:"POST",
        url:"system_setting.php",
        data:"p=add&username="+username+"&password="+password+"&nickname="+nickname+"&authority="+authority,
        success:function(data){
            viewData();
        }
    });
    

    And in php

    $page=isset($_POST['p'])?$_POST['p']:'';
    
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