duanmei2805 2015-08-23 14:10
浏览 173

无法从jquery中的Json_encode获取值

I have a file whichh is converting my php array to json

<?php
    include('lib/db.php');
    $cid = mysql_real_escape_string($_POST['id']);
    $q = rand(1, 2);
    $var = array();
    $rs1 = mysql_query("select * from questions where qid='$q' and sub_id='$cid'");
    while ($r1 = mysql_fetch_array($rs1)) {
        $var[] = array('qid' = > $r1['qid'], 'question' = > $r1['question'], 'ans' = > $r1['ans1'], 'ans2' = > $r1['ans2'], 'ans3' = > $r1['ans3'], 'ans4' = > $r1['ans4']);

    }
    print json_encode($var);    
?>

and the jquery code to load the value

$.ajax({
    url: "getquestion.php",
    type: "POST",
    data: "id=" + id,
    cache: false,
    dataType: "json",
    success: function (data, jqXHR) {

        if (data == null) {
            alert('nothing');

        } else {
            alert(data[0]);
        }

    }

});

But i am getting undefined in firebug console But i want the JSON value in jQuery variable.

  • 写回答

2条回答 默认 最新

  • doulang7699 2015-08-23 14:15
    关注

    Try setting the response content type to json

    header('Content-type: application/json');
    print json_encode($var);
    
    评论

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