dsf11t5u1651 2014-12-04 05:12
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两个具有相同值的活动中的两个ListView

I am doing an android project using php,mysql using xamp server. I have retrieved the values into a ListView from server database using json parser and displayed them successfully in activity1.

Now i need codings for, "when i press a button it should navigate into a new page named activity2 and the ListView values in activity1 should display in new ListView on activity2.

Thank you in advance.

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  • duanhuan1147 2014-12-04 05:31
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    in your starting intent you need to add data in intent :

     Intent intent = new Intent(this, abc.class);
      intent.putExtra("data", data);
       startActivity(intent);

    In your receiving intent you need to do:

    Intent i = getIntent();  
    stock_list = i.getStringArrayListExtra("data");

    The way you have it you've just created a new empty intent without any extras.

    If you only have a single extra you can condense this down to:

    stock_list = getIntent().getStringArrayListExtra("data");

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