正则表达式 - 从重复格式中提取字符串

Question

EDIT - SOLVED:
Thanks for the responses - I learned that this is actually in serialised format and that there's no need to process it using RegEx.

Apologies for the newb question - and I have tried many many variations, based on StackOverflow answers with no luck. I've also spent a while experimenting with an online Regex tool to try and solve this myself.

This is the string I'm checking :

i:0;s:1:"1";i:1;s:1:"3";i:2;s:1:"5";i:3;s:1:"6";

I'll settle for matching these strings :

i:0;s:1:"1";
i:1;s:1:"3";
i:2;s:1:"5";
i:3;s:1:"6";

But ideally I would like to capture all the values between quotes only.
(there could be anywhere between 1-10 of these kinds of entries)
i.e. regex_result = [1,3,5,6]

These are some of the regexes I've tried. I've only been able to either capture the first match, or the last match, but not all matches - I'm confused as to why the regex isnt "repeating" as I'd expected:

(i:.;s:1:".";)*

(i:.;s:1:".";)+

(i:.;s:1:".";)+?

Thanks

Answer 1

You can use this regex.

/(?<=:")\d+(?=";)/g

DEMO