I want to upload multiple image file to server and below is my code.The code upload only one image to server. I think problem in webservice. Please see the code and help me out please.
public void uploadMultiFile(ArrayList<String> imgPaths){
InputStream inputStream = null;
String result = "";
URL url = null;
HttpURLConnection conn = null;
DataOutputStream dos = null;
String lineEnd = "
";
String twoHyphens = "--";
String boundary = "*****";
int maxBufferSize = 1 * 1024 * 1024;
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
ArrayList<String> filenames = new ArrayList<String>();
int serverResponseCode = 0;
FileInputStream fileInputStream;
File sourceFile[] = new File[imgPaths.size()];
for (int i=0;i<imgPaths.size();i++){
sourceFile[i] = new File(imgPaths.get(i));
// Toast.makeText(getApplicationContext(),imgPaths.get(i),Toast.LENGTH_SHORT).show();
}
try {
url = new URL("url");
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE", "multipart/form-data");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
//filename set
for (int i=0;i<imgPaths.size();i++){
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyyMMddhhmmss");
String ext = sourceFile[i].getName().substring(sourceFile[i].getName().lastIndexOf(".") + 1);
String format = simpleDateFormat.format(new Date()) + i+"."+ext;
filenames.add(format);
}
for (int i=0;i<filenames.size(); i++) {
conn.setRequestProperty("uploaded_file"+i, filenames.get(i));
// Toast.makeText(getApplicationContext(),filenames.get(i),Toast.LENGTH_SHORT).show();
}
conn.setRequestProperty("filesname", "simple");
for (int i=0;i<filenames.size(); i++) {
if(i == 0){
fileInputStream = new FileInputStream(sourceFile[i]);
dos = new DataOutputStream(conn.getOutputStream());
String fnm = filenames.get(i);
dos.writeBytes(twoHyphens + boundary + lineEnd);
String fname = "uploaded_file" + i;
dos.writeBytes("Content-Disposition: form-data; name=\"" + fname + "\";filename=\""
+ filenames.get(i) + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
}else{
if(i >= 1) {
FileInputStream fileInputStream1 = new FileInputStream(sourceFile[i]);
dos.writeBytes(lineEnd);
dos.flush();
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
String fname = "uploaded_file" + i;
dos.writeBytes("Content-Disposition: form-data; name=\"" + fname + "\";filename=\""
+ filenames.get(i) + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream1.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream1.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream1.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream1.read(buffer, 0, bufferSize);
}
fileInputStream1.close();
}
}
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
final String serverResponseMessage = conn.getResponseMessage();
Log.i("uploadFile", "HTTP Response is : "
+ serverResponseMessage + ": " + serverResponseCode);
if (serverResponseCode == 200) {
inputStream = conn.getInputStream();
result = this.convertStreamToString(inputStream);
}
} catch (Exception e) {
e.printStackTrace();
Log.d("Error",e.getMessage());
}
}
Php script
This is my php script and i will send unique name if file from android app i didn't understand what to do.
$return_arr=array();
$Id=$_GET['count'];
$CurrentDate=time();
$total_files = count($_FILES);
$cnt = 0;
for ($x = 1; $x <= $total_files; $x++) {
$cnt = 0;
$param = "uploaded_file".$cnt;
if(isset($_FILES[$param]['name'][$x]) && $_FILES[$param]['name'][$x]!='')
{
$file_path = "../post_uploaded_images/";
$file_path = $file_path . basename( $CurrentDate ."_". $_FILES[$param]['name'][$x]);
if(@move_uploaded_file($_FILES[$param]['tmp_name'][$x], $file_path))
{
echo "success";
} else{
echo "fail";
}
}
$cnt = $cnt + 1;
}
