PHP或Javascript / Jquery - 计算新生儿/成人的年龄

Question

All functions that I've seen get the difference of years from birthdate, and I want to get the age in months or even days.

Sample in php:

$date = "2015-05-23";
/* whatever */
echo "Has 2 months and 8 days";

$date = "2012-10-30";
/* whatever */
echo "Has 2 years and 2 months";

Nevermind if it's in javascript/jquery or php.

Thanks people!

Answer 1

I modified some code to get what I wanted. This work perfectly, with all the exceptions (if some year/month/day is 0, not show).

I share with you my code in PHP, if someone need it too.

echo getAge("10-02-2014");

function getAge($fecha) {
/* $fecha => d-m-Y (in this format!!) */
$dob = strtotime($fecha);
$current_time = time();
$age_years = date('Y',$current_time) - date('Y',$dob);
$age_months = date('m',$current_time) - date('m',$dob);
$age_days = date('d',$current_time) - date('d',$dob);

if ($age_days<0) {
    $days_in_month = date('t',$current_time);
    $age_months--;
    $age_days= $days_in_month+$age_days;
}
if ($age_months<0) {
    $age_years--;
    $age_months = 12+$age_months;
}
$todayString = date('d',$current_time).'-'.date('m',$current_time).'-'.date('Y',$current_time);
/* keep in mind $today is always superior than $fecha */
if($fecha == $todayString){
   return "Today"; 
}  else if(date('Y',$dob) == date('Y',$current_time) && $age_months == "0") {
    return $age_days . " day".plural($age_days);
} else if(date('Y',$dob) == date('Y',$current_time) && $age_days != "0") {
    return $age_months ." month".plural($age_months)." and ".$age_days ." day".plural($age_days);
} else if(date('Y',$dob) == date('Y',$current_time) && $age_days == "0") {
    return $age_months . " month".plural($age_months);
} else if($age_years != "0" &&  $age_months != "0" && $age_days == "0") {
    return $age_years . " year".plural($age_years)." and ".$age_months." month".plural($age_months);
}  else if($age_years != "0" &&  $age_months == "0" && $age_days != "0") {
    return $age_years . " year".plural($age_years)." and ".$age_days." day".plural($age_days);
} else if($age_years != "0" &&  $age_months == "0" && $age_days == "0") {
    return $age_years . " year".plural($age_years);
} else { /* if you want to show the days always, add ----> ." and ".$age_days." day".plural($age_days) <---- below */
    return $age_years. " year".plural($age_years)." and ".$age_months." month".plural($age_months);
} }

function plural($num) {
if($num!="1"){
    return "s";
} }

Ah, remember, maybe you need to set the timezone before.

date_default_timezone_set("Europe/Madrid");