dsfds2353 2012-06-22 08:09
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在调用函数之后,无法使用php函数使用php读取插入mysql数据库中的行

called a function like :-

$setmessage = setlatestmessage($sessionid, $sendersuserid, $message1);

the function is in file functions.php, which i had included in this file The function is :-

function setlatestmessage($sessionid, $userid, $message, $status = 0) {
    $dbc = mysqli_connect(hostname, username, password, database)
            or die("Error connecting database");

    // there was no row, so just add a row
    $query2 = "insert into table(session_id, user_id, message, status) values ( $sessionid, $userid, '$message', $status)";
    mysqli_query($dbc, $query2);

    // if a row was affected, close connection and send true
    if (mysqli_affected_rows($dbc) == 1) {
        mysqli_close($dbc);
        return TRUE;
    }
    mysqli_close($dbc);
    return FALSE;
}

now, just after i had called this function, the script goes like

if (!$setmessage) {
                echo '<status>0</status>';
            } else {
                // fetch id of the row just inserted
                $query2 = "select id from game_messages where session_id = $sessionid and message = '$message1' and user_id = $sendersuserid order by datetime desc limit 1";
                $result2 = mysqli_query($dbc, $query2);

                if (mysqli_num_rows($result2) == 0) {
                    // if no row was returned
                    // case never should happen
                    echo '<status>10</status>';
                }
                else{echo'done';}

The output i get is 10.

However, if i just place a sleep(50) under the function call, or i just code what the function is doing, instead of the function call, i get correct output. Cant figure out why this is happening.

  • 写回答

1条回答 默认 最新

  • douhuiqi3855 2012-06-22 08:37
    关注

    It would be much easier and simpler if you would return the ID generated with your last insert query in setlatestmessage() function using mysqli_insert_id() or false on error. Then you would simply check:

    $messageID = setlatestmessage($sessionid, $sendersuserid, $message1);
    
    if ($messageID !== false)
    {
        echo '<status>0</status>';
    }
    else
    {
        echo '<status>10</status>';
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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