在函数中捕获异常，在try-catch中调用。 不起作用，为什么？

Question

I'm trying to call a function inside try block and if it fails, catch an exception. My code doesn't work right, what am I doing wrong? Sorry, I'm new on exceptions. Anybody? Any help appreciated :D

What I tried and what doesn't works:

function check ($func) {
    try {
        call_user_func($func);
    } catch (Exception $e) {
        echo "An error occurred.";
    }
}

function test () {
    echo 4/0;
}

check("test");

Returns just "INF" and "Division by zero" error, but should catch that exception and return "An error occurred."

Answer 1

Trying to throw an object that is not will result in a PHP Fatal Error using set_exception_handler().

For more details -

1- https://www.php.net/manual/en/language.exceptions.php#language.exceptions.catch

2- https://www.php.net/manual/en/class.errorexception.php

Try the below code, now error will go to catch.

   function exception_error_handler($severity, $message, $file, $line) {
    if (!(error_reporting() & $severity)) {
        // This error code is not included in error_reporting
        return;
    }

    if($message == 'Division by zero'){
        throw new DivisionByZeroError('Division By Zero Error');
    }else{
        throw new ErrorException($message, 0, $severity, $file, $line);
    }
}

set_error_handler("exception_error_handler");



function check ($func) {
    try {
        call_user_func($func);
    } 


    catch (DivisionByZeroError $e) {
        echo "An Division error occurred - ".$e->getMessage(); //$e->getMessage() will deisplay the error message
    }


    catch (Exception $e) {
        echo "An error occurred - ".$e->getMessage(); //$e->getMessage() will deisplay the error message
    }
}

function test () {


    echo 4/0;

}

check("test");