dongxianshuai8927 2014-07-25 17:11
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Php脚本在for(;;)循环后无法继续

I have a PHP script that queries a database and fills out some <option> tags inside a <select> tag. See code below:

$stmt = sqlsrv_query($dbc, $tsql, $params, $dbcOptions);
if($stmt === false) {
        die ( print_r (sqlsrv_errors(), true));
}
$rows = sqlsrv_num_rows($stmt);
#echo $rows.'rows';
echo '<!--'.$rows.'-->';
echo '<select onchange="getNamesByDep(this.value)">';
echo '<option value="">Select a Department. . .</option>';

for ($i = 1; i <= $rows; $i++)
{
        if(sqlsrv_fetch($stmt) !== false)
        {
                $DepName = sqlsrv_get_field($stmt,0);
                echo '    <option row="'.$i.'" value="'.$DepName.'">'.$DepName.'</option>'."
";
        }
}
echo '</select>';
echo 'Debugging';

It never echos </select> or Debugging to the HTML of the page.

I know that I configured $dbc, $tsql, $params, and $dbcOptions correctly because I am getting the desired results from my query.

Do I have a syntax error that my web server (WIMPServer) isn't catching?

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  • dsgdg46465 2014-07-25 17:16
    关注

    I think I found it:

    for ($i = 1; i <= $rows; $i++)
    

    You forgot the dollar sign before the second i. It should be like this:

    for ($i = 1; $i <= $rows; $i++)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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