dongxuxian6930 2011-11-04 12:08
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MySQL UPDATE无法正常工作

I have a bit of code which updates a table called job, but once the the page is executed it does not update the table. Here is the code:

$item = isset($_POST['item']);
$ref = isset($_POST['ref']);

$con = mysql_connect("$host","$username","$password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("$db_name", $con);

$sql="UPDATE job SET item = '$item' WHERE ref='$ref'";
if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }
header("location:index.php");

I have echoed out the $ref variable and it is there but it won't work if I put it in the WHERE clause.

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  • dongzhunnai0140 2011-11-04 12:12
    关注
    $ref = isset($_POST['ref']);
    

    I have echoed out the $ref variable and it is there

    You aren't assigning the actual value of $_POST['ref'], you're only assigning whether or not it is set. Try:

    $ref = isset($_POST['ref']) ? mysql_real_escape_string($_POST['ref']) : NULL;
    

    You can check your query by reading the SQL string you've created: exit($sql)

    See also: What is SQL injection?

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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