在php扩展中评估php代码

Question

I am writing a php extension( i am newbie) and now i encounter a weird problem:

Is there any way to evaluate php code in string INSIDE a php extension ?

for example bellow if zname would be "echo 'hello';" it will print hello not echo 'hello';

thanks in advance

PHP_FUNCTION(hello_greetme)
{
    zval *zname;

    if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "z", &zname) == FAILURE) {
        RETURN_NULL();
    }

    convert_to_string(zname);
    php_printf("Hello ");
    PHPWRITE(Z_STRVAL_P(zname), Z_STRLEN_P(zname));
    php_printf("
");


    RETURN_TRUE;
}

Answer 1

int eval_php_code(char *code) {
    int ret = 0;

    zend_try {
        ret = zend_eval_string(code, NULL, (char *)"" TSRMLS_CC);
    } zend_catch {

    } zend_end_try();

    return ret == FAILURE;
}

This should work for you.