通过URL传递字符串时忽略空格

Question

I am using the following code to display a hyperlink inside a table:

echo "<td><a href=http://www.smstoneta.com/show.php?opcode=TCP Y".">".
        $row['num_y']."</a></td>";

The hyperlink is displayed successfully but when I click on the hyperlink, the URL is

www.smstoneta.com/show.php?opcode=TCP

instead of

www.smstoneta.com/show.php?opcode=TCP Y

Why am I not getting the full URL?

Answer 1

Use urlencode()

$opCode = urlencode('TCP Y');
echo "<td><a href=http://www.smstoneta.com/show.php?opcode=".$opCode.">".$row['num_y']."</a></td>";