douciwang6819 2014-06-06 07:41
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php检查2个数组是否包含相同的值但是顺序不同

Is there a quick way in php to check if 2 arrays contain the same items while the order can be different.

This works for integer arrays How to check if two indexed arrays have same values even if the order is not same in PHP?

//these must be considered equal
array(1,2,3);
array(2,1,3);
array(3,1,2);

//However it must also be possible for strings
array("foo", "bar");
array("bar", "foo");
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  • dougan7657 2014-06-06 08:10
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    I found a pretty nice solution myself.

    $ar1 = array("hello","world","foo");//equals
    $ar2 = array("world","foo","hello");//equals
    $ar3 = array("hello","world","bar");//not equal
    
    $ar4 = array();
    //Add all items to a single array
    $ar4 = array_merge($ar1, $ar2);//equal 
    //OR
    $ar4 = array_merge($ar1, $ar3);//not equal
    //Remove all duplicates
    //$ar4 = array_unique($ar4); edited due to comment below
    $ar4 = array_flip($ar4);
    //if you want to user $ar4 later flip it again, its still faster than unique
    $ar4 = array_flip($ar4);
    
    $c1 = count($ar1);// = 3
    $c4 = count($ar4);// = 3 when the arrays were equal and is > 3 if not
    
    if($c1 === $c4){ //CODE }
    

    So for short this is

    $ar1 = array("hello","world","foo");
    $ar2 = array("world","foo","hello");
    $ar4 = array_merge($ar1, $ar2);
    //$ar4 = array_unique($ar4); edited due to comment below
    $ar4 = array_flip($ar4); 
    if(count($ar1) === count($ar4)){ //code }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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