PHP解析地址栏以转发到特定内容

Question

My webpage (www.gagandipsingh.com) is coded mostly on one page, with links calling the following script, which show/hide certain div sections...

    <script type="text/javascript">
    function show() {
        document.getElementById(arguments[0]).style.display='block';
        for (var i = 1; i < arguments.length; i++) {
            // alert(arguments[i]);
             document.getElementById(arguments[i]).style.display='none';
        }
        return false;
    } 
</script>

My question is, is it possible to parse the address bar so that a certain div may be shown/hidden? I found i could get variables (ex: gagandipsingh.com?p=code) so I attempted my requirment with the following...

<?php 
    echo '<script type="text/javascript" src="show_hide.js"></script>';
    if (isset($_GET['p'])) 
    { 
        $page = $_GET['p'];
        if ($page == 'code'){
            echo "show('Code','Media','Home', 'Resume','Contact')";
        }
    } 
    else 
    { 
        echo "Variable not set."; 
    } 
?>

which did not work; the function never gets called, just prints that message. You can see an example of that at http://gagandipsingh.com/test/?p=code

Any advice would be greatly appreciated.

Answer 1

If you want the function call to be executed instead of just being displayed as part of the web page, you have to enclose it in a <script> tag.

<?php 
    echo '<script type="text/javascript" src="show_hide.js"></script>';
    if (isset($_GET['p'])) 
    { 
        $page = $_GET['p'];
        if ($page == 'code'){
            echo "<script type='text/javascript'>show('Code','Media','Home', 'Resume','Contact');</script>";
        }
    } 
    else 
    { 
        echo "Variable not set."; 
    } 
?>