duanjie2701 2012-03-26 08:59
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换行内容如何成为一行段落?

*strong text*what i want to do is from my breakline content to one line paragraph

example my var_dump result:

string(212) "(73857,"2012-02-02 03:18:44","TXT",60143836234);"

string(122) "(73858,"2012-02-02 03:20:08","WAP",60143836234);"

string(211) "(73859,"2012-02-02 08:21:47","TXT",60163348563,);"

What i want to become:

string(555) "(73857,"2012-02-02 03:18:44","TXT",60143836234);(73858,"2012-02-02 03:20:08","WAP",60143836234);(73859,"2012-02-02 08:21:47","TXT",60163348563,);"

update (here is my code, $i is the line break records, if I able to make the breakline to one line, i will put in a new file )

foreach($get_line_feed_content as $i) {
$add_special_char = "(".$i.");";

var_dump($add_special_char);

    if(!empty($i)){


        $stringData = $final_content;
        fwrite($save, $stringData);
        fclose($save);
    }
}

any idea?

Thank and highly appreciated your answer

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2条回答 默认 最新

  • drl37530 2012-03-26 09:00
    关注

    Did you just want to glue the strings together? I don't see any line breaks from your dumps.

    If that's the case, just do:

    $finalString = $string1 . $string2 . $string3;
    var_dump($finalString); //Strings should be glued as one.
    

    If, however, each line is represented as an element in an array:

    $stringsArray = array('string1', 'string2', 'string3');
    $finalString = implode("", $stringsArray);
    var_dump($finalString);
    

    With your most recent update, this is what I would do:

    $newString = '';
    
    foreach($get_line_feed_content as $i) { 
      $newString  .= "(".$i.");"; //concatenate
    
      var_dump($newString); //You will get a lot of dumps and with each dump, a new string should be appended to it. 
    
        if(!empty($i)){ 
            fwrite($save, $newString); 
            fclose($save); 
        } 
    } 
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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